Click Here to
Order this information in Print

Click Here to
Order this information on CD-ROM

Click Here to
Download this information in PDF Format

     

Click here to make tpub.com your Home Page

Figure 2-11.—Multiplication of forces.
Back | Up | Next

Click here for a printable version

Google


Web
www.tpub.com

Home


   
Information Categories
.... Administration
Advancement
Aerographer
Automotive
Aviation
Combat
Construction
Diving
Draftsman
Engineering
Electronics
Food and Cooking
Math
Medical
Music
Nuclear Fundamentals
Photography
Religion
USMC
   
Products
  Educational CD-ROM's
Printed Manuals
Downloadable Books
   

 

Back
Pressure and Force in Fluid Power Systems
Up
Fluid Power - Intro to Hydraulics, Pneumatics, and how it all works
Next
Figure 2-12.—Differential areas on a piston.

is  provided  by  the  equipment  to  which  the output   piston   is   attached.   The   force   of   re- sistance  acts  against  the  top  of  the  output piston.   The   pressure   created   in   the   system by  the  input  piston  pushes  on  the  underside  of the  output  piston  with  a  force  of  10  pounds  on each  square  inch. In this case, the fluid column has a uniform cross  section,  so  the  area  of  the  output  piston is  the  same  as  the  area  of  the  input  piston, or  10  square  inches.   Therefore,  the  upward force   on   the   output   piston   is   100   pounds (10 psi x 10 sq. in.), the same as the force applied to the input piston. All that was accomplished in this system was to transmit the 100-pound force around the bend. However, this principle under- lies  practically  all  mechanical  applications  of  fluid power. At  this  point  you  should  note  that  since Pascal’s  law  is  independent  of  the  shape  of the   container,   it   is   not   necessary   that   the tube  connecting  the  two  pistons  have  the  same cross-sectional area of the pistons. A connection of  any  size,  shape,  or  length  will  do,  as  long  as an unobstructed passage is provided. Therefore, the system shown in figure 2-10, with a relatively small,  bent  pipe  connecting  two  cylinders, will act exactly the same as the system shown in figure  2-9. MULTIPLICATION  OF  FORCES.—  Con- sider  the  situation  in  figure  2-11,  where  the  input piston  is  much  smaller  than  the  output  piston. Assume  that  the  area  of  the  input  piston  is  2 square inches. With a resistant force on the output piston a downward force of 20 pounds acting on the input piston creates a pressure of or 10 psi Figure 2-10.—Transmitting force through a small pipe. Figure  2-11.—Multiplication  of  forces. in the fluid. Although this force is much smaller than the force applied in figures 2-9 and 2-10, the pressure is the same. This is because the force is applied  to  a  smaller  area. This pressure of 10 psi acts on all parts of the fluid  container,  including  the  bottom  of  the output  piston.  The  upward  force  on  the  output piston  is  200  pounds  (10  pounds  of  pressure  on each square inch). In this case, the original force has been multiplied tenfold while using the same pressure in the fluid as before. In any system with these  dimensions,  the  ratio  of  output  force  to input force is always ten to one, regardless of the applied  force.  For  example,  if  the  applied  force of the input piston is 50 pounds, the pressure in the  system  will  be  25  psi.  This  will  support  a resistant force of 500 pounds on the output piston. The system works the same in reverse. If we change the applied force and place a 200-pound force  on  the  output  piston  (fig.  2-11),  making  it the  input  piston,  the  output  force  on  the  input piston  will  be  one-tenth  the  input  force,  or  20 pounds.  (Sometimes  such  results  are  desired.) Therefore,  if  two  pistons  are  used  in  a  fluid  power system, the force acting on each piston is directly proportional  to  its  area,  and  the  magnitude  of each force is the product of the pressure and the area  of  each  piston. Note the white arrows at the bottom of figure 2-11  that  indicate  up  and  down  movement.  The movement they represent will be explained later in the discussion of volume and distance factors. 2-7

Privacy Statement - Press Release - Copyright Information. - Contact Us - Support Integrated Publishing